The mass of a particle at rest (the mass of E=mc²) in an absolute frame is given by the crossing of the gravitons of the vacuum through the particle .
If the particle is near a mass M its mass is changed because it collects more gravitons , and for the weighty mass we have :

In this formula img-014 is the number of new gravitons which are caught by a mass m placed at the distance R of M during T , and a=Hc , where H is the Hubble ‘s constant and
a is a quantum of acceleration given by the crossing of the graviton through the particle . Moreover the number of efficient gravitons , which move the particle is A/a , where A is the acceleration , and we have:
the inert mass
If the number of efficient gravitons is the same of the number of collected gravitons we have the classical Newton’s law and weighty mass is the same of inert mass  and the Relativity is good . But it is not always the case,especially at big distance,when the number of gravitons is insufficient for all particles and the Relativity is not good, and we have :
img-016                             img-001                         
with img-027and 


For many things we determine the Newton's law habitual of the all things and we join a .

Solar system

If we use the new Newton’s law for the solar system we have not great perturbations for the planets . We have no displacement of the perihelion . The Binet’s formula gives an ellipse which have a half-axis which is more short about 220 km , and a period which is more short about 70 s for our planet , than with the classic law. It is necessary to change the mass of the sun.
The change of gravitation would be about 5 . 10 14 m .Pluton is at 6 . 10 12 m . The perturbations are small.
We have also the Pioneer’s effect . The alteration of the trajectory of this satellite have a good explanation with the new Newton’s law . But it is necessary to have confirmation with another satellites.


For the galaxies we take the model of our galaxy . As for as 15000 yl we have the classical Newton’s law which prevails . After as for as about 55000yl the increase of aR compensates for the decrease of GM/R . The speeds of the stars are nearly the same,we have V4=4MGHC ,where M is the mass of the core of the galaxy(where the law go from r² to 1/r) , G the constant of the gravitation , H the Hubble's constant and C the speed of the light. After this speed increases with a law v 2=aR . We have this results if we make the calculation in a spherical system , with a weighty central mass , which is not exactly the case of our galaxy .
For the galaxies we have another result . To explain the rotation of the galaxies it is necessary to have a collision at the beginning . This collision is a collision of clouds of hydrogen or of small galaxies . The symmetry is a symmetry at 180 degrees . But when the action of a becomes preponderant we have a symmetry at 120 degrees (three arms) ..This symmetry would be the symmetry of the old calm spiral galaxies.

Pack of Galaxies

The presence of an acceleration a increases the cohesion of the pack . We have a change in the gravitation for a radius about the square root of GM/a . Somebody says we have a ring of dark matter of this size . In fact the acceleration a increases the quality of lens gravity with a supplementary deviation β=2α with:


When a photon go at R metres of the centre of the pack .
Moreover a particle of mass m can because the gravity have a speed
which is the square root of 2aR’ , where R’ is the radius of the pack . This speed gives an emission of X rays with :

λ  =


Where h is the Planck’s constant.
Somebody says we have a temperature T =img-021Where k is the Boltzmann’s constant
In this case also it is not necessary to have dark matter to explain this X rays.


The trajectories of the galaxies are nearly ellipses. But the main thing is to evaluate the red shift.

We have Z' =      img-022

E is the energy, U is the potential of gravitation where is the galaxy and V is its speed.

A circular approximation gives : img-028
Int this formula we have b = img-024
  , R is the radius of the bulb of the univers, and M is its mass, x is the distance between the galaxy and the observer with D=c/H as unit of length.We have also Z"=-1+img-026       ;, which is the red shift given by the walking of the photon in the universe , and gives a good solution for the Hubble constant.

And Z = Z' + Z" gives a good solution for the supernovae.
The point of inflexion gives b = 0,27 for x = 0,25 and 28.10-28Kg/m3 for the density of the universe. If V is nearly C and U nearly C² it is necessary to use the formulas of the Relativity.
The red or the blue shifts of Doppler's effect are small except very particular cases.

The gravitation is given by an exchange of gravitons .
Weighty mass and inert mass are not always the same .Therefore we have a new Newton’s law and no dark matter,no dark energy and no big bang , but many small bangs .If the red shift of the inverse point is nearly 0,6 and its distance nearly 5 milliards yl , we have the Milky Way nearly the center of the universe.We see also universe is a black hole with R=D.


  Black holes have gravity , therefore they emit gravitons . These gravitons come from the matter , which is destroyed . The black hole  vanishs.                                         
    The numbers of gravitons in and out the matter are nearly . Perhaps we have a solution for the antimatter.
  The undulation of the fluctuations (neglected the 80 millionth of K) of the 2,7K explains the birth of the hydrogen atom with protons and electrons . We have the energy levels of this atom.But it is necessary to have many small bangs and no big bang to have good results.The 80 millionth of K is given by the       fashioning of the hélium.                           We have also H/c=144 =2x72 with megaparsec and km/s , and this result is dependent on the distance.                

FaLang translation system by Faboba